Lesson 3.1.6.2
3.1.6.2 Equilibrium constant Kc for homogeneous systems Quiz: AQA Chemistry, Unit 1
20 questions
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Lesson 3.1.6.2, Equilibrium constant Kc for homogeneous systems: 20 multiple choice questions for the AQA Chemistry (7405), Unit 1: Physical chemistry, written with Revision Ninja.
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The 20 questions
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Which expression is the correct Kc for the homogeneous equilibrium 2A(g) + B(g) <=> C(g)?
- Kc = [C]^2/([A] [B])
- Kc = [A][B]/[C]
- Kc = [C]/([A]^2 [B])
- Kc = [A]^2 [B]/[C]
-
Which expression is the correct Kc for the equilibrium N2O4(g) <=> 2NO2(g)?
- Kc = [NO2]/[N2O4]
- Kc = [N2O4]/[NO2]^2
- Kc = [NO2]^2/[N2O4]
- Kc = [NO2]^2 [N2O4]
-
At equilibrium for H2(g) + I2(g) <=> 2HI(g), [H2] = 0.10, [I2] = 0.10 and [HI] = 0.80 mol dm^-3. What is Kc?
- 16
- 0.016
- 64
- 8
-
For 2SO2(g) + O2(g) <=> 2SO3(g), at equilibrium [SO2] = 0.20, [O2] = 0.10 and [SO3] = 0.50 mol dm^-3. What is Kc?
- 62.5 dm^3 mol^-1
- 250 dm^3 mol^-1
- 0.4 dm^3 mol^-1
- 2.5 dm^3 mol^-1
-
For A + B <=> C + D, the equilibrium concentrations are [A] = 0.50, [B] = 0.20, [C] = 0.40 and [D] = 0.10 mol dm^-3. What is Kc?
- 2.5
- 0.4
- 4.0
- 0.04
-
The equilibrium PCl5(g) <=> PCl3(g) + Cl2(g) has [PCl5] = 0.20, [PCl3] = 0.40 and [Cl2] = 0.40 mol dm^-3. What is Kc?
- 0.8 mol dm^-3
- 1.6 mol dm^-3
- 0.4 mol dm^-3
- 0.2 mol dm^-3
-
In an equilibrium 2HI <=> H2 + I2 in a 2 dm^3 vessel, the amounts at equilibrium are 0.4 mol HI, 0.1 mol H2 and 0.1 mol I2. What is Kc?
- 0.0625
- 0.0156
- 0.0313
- 0.2500
-
What are the units of Kc for the equilibrium N2(g) + 3H2(g) ⇌ 2NH3(g)?
- mol² dm⁻⁶
- mol⁻¹ dm³
- mol⁻² dm⁶
- mol dm⁻³
-
What are the units of Kc for the homogeneous equilibrium A(g) + B(g) ⇌ 2C(g)?
- mol² dm⁻⁶
- mol⁻¹ dm³
- No units
- mol dm⁻³
-
Which factor alters the numerical value of the equilibrium constant Kc for a reaction?
- Temperature
- Concentration
- Catalyst
- Pressure
-
What happens to the value of Kc for an exothermic reaction when temperature is increased?
- Remains unchanged
- Decreases
- Doubles
- Increases
-
What happens to the value of Kc when reactant concentration is increased at constant temperature?
- Increases
- Remains unchanged
- Becomes zero
- Decreases
-
If a temperature change shifts an equilibrium position to the right, what happens to Kc?
- Increases
- Becomes zero
- Decreases
- Remains unchanged
-
How does adding a catalyst affect the numerical value of the equilibrium constant Kc?
- Increases Kc
- No effect
- Decreases Kc
- Doubles Kc
-
What determines the powers used in the expression for the equilibrium constant Kc?
- Activation energies
- Temperature changes
- Stoichiometric coefficients
- Reactant concentrations
-
For the equilibrium 2A(g) + B(g) <=> 2C(g) + D(g), which is the correct expression for Kc?
- Kc = [C]^2 [D]^2/([A]^2 [B]^2)
- Kc = [C][D]/([A][B])
- Kc = [C]^2 [D]/([A]^2 [B])
- Kc = [A]^2 [B]/([C]^2 [D])
-
In esterification with Kc = 4, what is the new Kc if initial reactant moles double at constant temperature?
- 2
- 4
- 8
- 16
-
For N2O4(g) <=> 2NO2(g), a vessel has [N2O4] = 0.040 and [NO2] = 0.040 mol dm^-3 at equilibrium. What is Kc?
- 25 mol dm^-3
- 0.0016 mol dm^-3
- 1.0 mol dm^-3
- 0.040 mol dm^-3
-
A mixture contains 0.30 mol of A and 0.30 mol of B in 1.0 dm^3 and reaches equilibrium with 0.10 mol of C for A + B <=> C. What is Kc?
- 0.10 dm^3 mol^-1
- 0.033 dm^3 mol^-1
- 2.5 dm^3 mol^-1
- 10 dm^3 mol^-1
-
For N2O4(g) <=> 2NO2(g), Kc = 0.50 mol dm^-3 at a fixed temperature. If [N2O4] = 0.20 mol dm^-3 at equilibrium, what is [NO2]?
- 0.32 mol dm^-3
- 2.5 mol dm^-3
- 0.40 mol dm^-3
- 0.10 mol dm^-3
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