Lesson 3.1.8.2
3.1.8.2 Gibbs free-energy change, ∆G, and entropy change, ∆S Quiz: AQA Chemistry, Unit 1
20 questions
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Lesson 3.1.8.2, Gibbs free-energy change, ∆G, and entropy change, ∆S: 20 multiple choice questions for the AQA Chemistry (7405), Unit 1: Physical chemistry, written with Revision Ninja.
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The 20 questions
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What value must Gibbs free-energy change, ΔG, have for a reaction to be feasible?
- Zero or negative
- Strictly positive
- Strictly zero
- Zero or positive
-
Which relationship links the Gibbs free-energy change, enthalpy change and entropy change?
- delta G = delta H / T + delta S
- delta G = T delta H - delta S
- delta G = delta H + T delta S
- delta G = delta H - T delta S
-
For NH3 synthesis, delta H = -92 kJ/mol and delta S = -198 J K^-1 mol^-1. What is delta G at 298 K?
- About +33 kJ/mol
- About -59 kJ/mol
- About -92 kJ/mol
- About -33 kJ/mol
-
For NH3 synthesis with delta H = -92 kJ/mol and delta S = -198 J K^-1 mol^-1, above what temperature does the reaction become non-feasible?
- About 298 K
- About 192 K
- About 465 K
- About 930 K
-
Using standard entropy values for CaCO3 = 93, CaO = 40 and CO2 = 214 J K^-1 mol^-1, what is the entropy change for CaCO3 -> CaO + CO2?
- -161 J K^-1 mol^-1
- +347 J K^-1 mol^-1
- +161 J K^-1 mol^-1
- +54 J K^-1 mol^-1
-
For CaCO3 -> CaO + CO2 with delta H = +178 kJ/mol and delta S = +161 J K^-1 mol^-1, what is the minimum temperature at which the decomposition is feasible?
- About 161 K
- About 1106 K
- About 2 K
- About 178 K
-
Which physical state change always results in a positive entropy change?
- Liquid to gas
- Gas to liquid
- Gas to solid
- Liquid to solid
-
Besides enthalpy change and temperature, what property determines the feasibility of a reaction?
- Rate constant
- Bond enthalpy
- Entropy change
- Activation energy
-
At what temperature condition is a reaction with ΔH = -90 kJ mol⁻¹ and ΔS = -150 J K⁻¹ mol⁻¹ feasible?
- Above 600 K
- Below 600 K
- Above 0.6 K
- Below 0.6 K
-
For a reaction with delta H = -50 kJ/mol and delta S = -100 J K^-1 mol^-1 at 300 K, what is delta G?
- -50 kJ/mol
- -20 kJ/mol
- +20 kJ/mol
- -80 kJ/mol
-
Which combination of ΔH and ΔS signs makes a reaction feasible only at high temperatures?
- +ΔH and +ΔS
- -ΔH and +ΔS
- +ΔH and -ΔS
- -ΔH and -ΔS
-
Which combination of ΔH and ΔS signs makes a reaction feasible only at low temperatures?
- -ΔH and -ΔS
- -ΔH and +ΔS
- +ΔH and +ΔS
- +ΔH and -ΔS
-
Estimate the entropy change for vaporising water at its boiling point of 373 K, given delta Hvap = +40.7 kJ/mol.
- About +0.109 J K^-1 mol^-1
- About +273 J K^-1 mol^-1
- About +109 J K^-1 mol^-1
- About +40.7 J K^-1 mol^-1
-
On a graph of delta G against temperature T, what does the gradient of the straight line represent?
- delta H
- delta S
- delta G
- -delta S
-
A reaction has delta H = -40 kJ/mol and delta S = -100 J K^-1 mol^-1. What is delta G at 400 K?
- -80 kJ/mol
- 0 kJ/mol
- +80 kJ/mol
- -40 kJ/mol
-
A reaction has delta H = +50 kJ/mol and delta S = +0.1 kJ K^-1 mol^-1. At what temperature does delta G = 0?
- 500 K
- 1000 K
- 50 K
- 5 K
-
Which expression correctly rearranges delta G = delta H - T delta S to give the entropy change?
- delta S = T (delta H - delta G)
- delta S = (delta G - delta H)/T
- delta S = (delta H - delta G)/T
- delta S = (delta H + delta G)/T
-
How can a reaction with negative ΔH and negative ΔS be made feasible?
- Lowering the temperature
- Adding a catalyst
- Increasing the pressure
- Raising the temperature
-
How do you convert ΔS from J K⁻¹ mol⁻¹ to kJ K⁻¹ mol⁻¹?
- Add 273
- Divide by 100
- Divide by 1000
- Multiply by 1000
-
If ΔH is negative and ΔS is positive, at what temperatures is the reaction feasible?
- High temperatures only
- Low temperatures only
- No temperatures
- All temperatures
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