Lesson A15
A15 calculate or estimate gradients of graphs and areas under graphs (including quadratic... Quiz: Pearson Edexcel Maths, Unit 2
20 questions
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Lesson A15, calculate or estimate gradients of graphs and areas under graphs (including quadratic...: 20 multiple choice questions for the Pearson Edexcel GCSE Maths (1MA1), Unit 2: Algebra, written with Revision Ninja.
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The 20 questions
-
How do you estimate the gradient of a curve at a single point?
- find midpoint
- draw tangent
- integrate function
- calculate chord length
-
The area under a velocity-time graph gives
- distance travelled
- the gradient
- acceleration
- average speed
-
The gradient of a distance-time graph represents
- speed
- distance
- acceleration
- time taken
-
The gradient of a velocity-time graph represents
- acceleration
- distance
- speed
- displacement
-
Which method is used to estimate the area under a curve?
- Square counting
- Trapezia strips
- Triangle splitting
- Rectangle circumscribing
-
What does the gradient of a value-time graph represent?
- Initial value
- Rate of change
- Total value
- Average value
-
What does a negative gradient on a distance-time graph indicate?
- Speeding up
- Returning home
- Stationary motion
- Moving forwards
-
What does the section below the time axis on a velocity-time graph represent?
- Deceleration
- Reverse motion
- Zero speed
- Negative distance
-
A tangent to a distance-time graph passes through (2, 40) and (6, 120). Its gradient is
- 5 m/s
- 160 m/s
- 20 m/s
- 80 m/s
-
A velocity-time trapezium has parallel sides 4 m/s and 10 m/s and width 6 s. Its area is
- 42 m
- 84 m
- 60 m
- 24 m
-
A tangent at x = 2 on a curve passes through (1, 3) and (3, 7). Its gradient is
- 0.5
- 4
- -2
- 2
-
A value rises from £200 to £260 over 4 years. The average rate of change is
- £60 per year
- £200 per year
- £4 per year
- £15 per year
-
A velocity falls from 12 m/s to 0 m/s over 4 s in a straight line. The distance is
- 24 m
- 48 m
- 6 m
- 12 m
-
A distance of 150 m is covered in 10 s. The average speed is
- 15 m/s
- 150 m/s
- 10 m/s
- 1500 m/s
-
Using more strips when estimating the area under a curve results in what?
- Constant error
- Zero error
- Higher accuracy
- Lower accuracy
-
The chord from (2, 4) to (3, 9) on y = x^2 gives an approximate gradient of
- 5
- 13
- 4
- 9
-
On a distance-time graph, at a later time the curve is steeper. The speed then is
- unchanged
- zero
- smaller
- greater
-
Velocity is 4 m/s for 2 s, then -3 m/s for 3 s. The net displacement is
- -17 m
- 17 m
- -1 m
- 1 m
-
What does the area under a rate-of-change graph represent?
- Final rate
- Average rate
- Maximum rate
- Total change
-
A car accelerates uniformly from 0 to 20 m/s in 8 s. The distance covered is
- 20 m
- 40 m
- 80 m
- 160 m
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