Lesson A18
A18 solve quadratic equations (including those that require rearrangement) algebraically... Quiz: Pearson Edexcel Maths, Unit 2
20 questions
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Lesson A18, solve quadratic equations (including those that require rearrangement) algebraically...: 20 multiple choice questions for the Pearson Edexcel GCSE Maths (1MA1), Unit 2: Algebra, written with Revision Ninja.
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The 20 questions
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The quadratic formula gives the solutions of ax^2 + bx + c = 0 as
- x = (b ± √(b^2 + 4ac)) / 2a
- x = -b/2a ± c
- x = (-b ± √(b^2 - 4ac)) / 2a
- x = (-b ± √(b^2 - 4ac)) / a
-
The standard form of a quadratic equation is
- ax^2 + bx + c = 0
- a/x + b = c
- ax + b = 0
- ax^3 + bx + c = 0
-
The solutions of x^2 + 5x + 6 = 0 are
- x = -1 or x = -6
- x = -2 or x = -3
- x = -5 or x = -6
- x = 2 or x = 3
-
What must you do before factorising a quadratic equation to solve it?
- Isolate x squared
- Square root
- Equals zero
- Divide by two
-
Completing the square turns x^2 + 6x into
- (x + 3)^2 - 9
- (x + 3)^2 + 9
- (x + 6)^2 - 36
- (x - 3)^2 - 9
-
The equation x^2 - 4x = 0 has how many solutions?
- one
- three
- none
- two
-
A quadratic equation has at most how many solutions?
- one
- three
- four
- two
-
How should you solve x^2 = 16 to find all values of x?
- Only 4
- Only -4
- 8 and -8
- Plus or minus 4
-
The solutions of x^2 - 7x + 12 = 0 are
- x = 1 or x = 12
- x = -3 or x = -4
- x = 2 or x = 6
- x = 3 or x = 4
-
The solutions of x^2 + 4x - 5 = 0 are
- x = -1 or x = 5
- x = 4 or x = -5
- x = 1 or x = -5
- x = 5 only
-
The solutions of 2x^2 - 8 = 0 are
- x = 1 or x = -1
- x = 2 or x = -2
- x = 8
- x = 4 or x = -4
-
Solving x^2 + 6x + 2 = 0 by completing the square gives
- x = -3 ± √7
- x = -6 ± √2
- x = -3 ± 7
- x = 3 ± √7
-
Using the quadratic formula on 2x^2 + 3x - 2 = 0, the solutions are
- x = 0.5 or x = -2
- x = 0.5 or x = 2
- x = -0.5 or x = 2
- x = 1 or x = -2
-
The solutions of x^2 = 2x + 8 are
- x = 4 or x = -2
- x = 2 or x = -8
- x = 8 or x = -1
- x = -4 or x = 2
-
A rectangle has length x + 3 cm and width x cm, with area 40 cm^2. The value of x is
- x = 5 cm
- x = 8 cm
- x = -8 cm
- x = 3 cm
-
The solutions of x(x + 2) = 15 are
- x = 15 or x = -2
- x = 3 or x = -5
- x = 1 or x = -15
- x = -3 or x = 5
-
The solutions of x^2 - 4x - 1 = 0 are
- x = 2 ± √5
- x = 2 ± √3
- x = -2 ± √5
- x = 4 ± √5
-
The solutions of x^2 - 3x - 2 = 0, to 2 decimal places, are
- x = 3.56 or x = -0.56
- x = 3.56 or x = 0.56
- x = 1.56 or x = -1.56
- x = 4.12 or x = -1.12
-
The solutions of 3/x = x - 2 are
- x = 3 only
- x = -3 or x = 1
- x = 3 or x = -1
- x = 2 or x = -3
-
If x^2 + bx + c = 0 has roots -3 and 5, then
- b = -2 and c = 15
- b = 8 and c = -15
- b = 2 and c = 15
- b = -2 and c = -15
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