Lesson 13.1.1
13.1.1 Conditions and equations for simple harmonic motion Quiz: Pearson Edexcel Physics, Unit 13
20 questions
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Lesson 13.1.1, Conditions and equations for simple harmonic motion: 20 multiple choice questions for the Pearson Edexcel Physics (9PH0), Unit 13: Oscillations, written with Revision Ninja.
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The 20 questions
-
In simple harmonic motion, acceleration is directly proportional to which quantity?
- Displacement
- Velocity
- Time
- Frequency
-
In the SHM restoring force equation F = -kx, what does the minus sign indicate?
- Displacement is constant
- Force opposes displacement
- Stiffness increases
- Force increases speed
-
Which relationship links the angular frequency ω to the period T?
- ω = T^2 / (2 π)
- ω = T / (2 π)
- ω = 2 π / T
- ω = 2 π T
-
What is the period of a mass-spring oscillator of mass m and spring constant k?
- T = sqrt(m / k)
- T = 2 π sqrt(m / k)
- T = 2 π m / k
- T = 2 π sqrt(k / m)
-
For small angles, the period of a simple pendulum does not depend on which quantity?
- Pendulum length
- Gravitational field strength
- Pivot friction
- Bob mass
-
A mass of 0.50 kg is on a spring of stiffness 200 N m^-1. What is its period of oscillation?
- 0.063 s
- 0.31 s
- 0.0050 s
- 1.6 s
-
A simple pendulum of length 1.0 m is at a place where g = 9.81 m s^-2. What is its period for small swings?
- 4.0 s
- 0.32 s
- 2.0 s
- 1.0 s
-
An oscillator has angular frequency 12.6 rad s^-1 and displacement 0.050 m. What is its acceleration?
- -2.0 m s^-2
- -79 m s^-2
- -0.79 m s^-2
- -7.9 m s^-2
-
A system oscillates at frequency 5 Hz. What is its angular frequency?
- 0.2 rad s^-1
- 10 rad s^-1
- 5 rad s^-1
- about 31 rad s^-1
-
A spring extended by 0.030 m has spring constant 150 N m^-1. What is the restoring force?
- 4.5 N
- 5000 N
- 0.2 N
- 450 N
-
A 0.20 kg mass oscillates on a spring with period 0.40 s. What is the spring constant?
- about 197 N m^-1
- about 4.9 N m^-1
- about 49 N m^-1
- about 0.13 N m^-1
-
What length of simple pendulum gives a period of 1.0 s, using g = 9.81 m s^-2?
- 0.50 m
- 1.0 m
- 0.10 m
- 0.25 m
-
Which system undergoes simple harmonic motion for small oscillations?
- Rotating bicycle wheel
- Bouncing rubber ball
- Mass on spring
- Falling raindrop
-
For a simple pendulum, SHM requires which mathematical approximation?
- sin θ ≈ 1
- tan θ ≈ cos θ
- sin θ ≈ θ
- cos θ ≈ θ
-
Why does the period of a simple pendulum increase at large amplitudes?
- Restoring force non-linear
- Bob mass increases
- String length grows
- Gravity decreases rapidly
-
If the amplitude of a simple harmonic oscillator is doubled, by what factor does its total energy change?
- 2
- 1/2
- 4
- 8
-
Two identical springs are connected in parallel to a mass. How does the period change?
- Doubled
- Halved
- Multiplied by √2
- Multiplied by 1/√2
-
What is the defining direction of a restoring force in simple harmonic motion?
- Away from equilibrium
- Along tangent line
- Towards equilibrium
- Perpendicular to motion
-
In simple harmonic motion, which quantity is directly proportional to negative displacement?
- Velocity
- Acceleration
- Kinetic energy
- Time period
-
Which quantity is independent of the amplitude in SHM?
- The maximum acceleration
- The period
- The maximum speed
- The total energy
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