Lesson 2.1.2
2.1.2 Displacement, velocity and acceleration graphs Quiz: Pearson Edexcel Physics, Unit 2
20 questions
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Lesson 2.1.2, Displacement, velocity and acceleration graphs: 20 multiple choice questions for the Pearson Edexcel Physics (9PH0), Unit 2: Mechanics, written with Revision Ninja.
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The 20 questions
-
The gradient of a displacement-time graph gives:
- Momentum
- Force
- Velocity
- Acceleration
-
The area under a velocity-time graph represents:
- Force
- Velocity
- Acceleration
- Displacement
-
The gradient of a velocity-time graph gives:
- Velocity
- Acceleration
- Jerk
- Displacement
-
A velocity-time graph rises in a straight line from 0 at t = 0 to 20 m s^-1 at t = 4 s, then stays constant at 20 m s^-1 until t = 10 s. What is the total displacement?
- 40 m
- 200 m
- 160 m
- 120 m
-
What does a steadily increasing gradient on a displacement-time graph represent?
- Increasing velocity
- Decreasing velocity
- Constant velocity
- Constant displacement
-
An acceleration-time graph is a horizontal line at 2 m s^-2 from t = 0 to t = 5 s. What is the change in velocity?
- 5 m s^-1
- 0.4 m s^-1
- 2 m s^-1
- 10 m s^-1
-
What does a negative gradient on a velocity-time graph with positive velocity represent?
- Positive acceleration
- Increasing velocity
- Zero acceleration
- Negative acceleration
-
What quantity is given by the gradient of a tangent to a velocity-time graph?
- Average acceleration
- Instantaneous acceleration
- Instantaneous velocity
- Total displacement
-
A displacement-time graph is a horizontal straight line. What is the velocity?
- Zero
- Increasing
- Constant and non-zero
- Negative
-
A velocity-time graph starts at 2 m s^-1 and has a gradient of 3 m s^-2 for 4 s. What is the final velocity?
- 6 m s^-1
- 14 m s^-1
- 10 m s^-1
- 12 m s^-1
-
What does an area bounded below the time axis on a velocity-time graph represent?
- Positive displacement
- Negative velocity
- Negative displacement
- Negative acceleration
-
A car's velocity rises uniformly from 0 to 10 m s^-1 in 5 s and then falls uniformly to 0 in a further 10 s. What is the total distance travelled?
- 25 m
- 150 m
- 50 m
- 75 m
-
Using the motion in the previous scenario (75 m in 15 s), what is the average velocity over the whole journey?
- 7.5 m s^-1
- 5 m s^-1
- 2.5 m s^-1
- 10 m s^-1
-
A displacement-time graph passes through (2 s, 4 m) and (6 s, 20 m). What is the velocity between these points?
- 4 m s^-1
- 16 m s^-1
- 0.25 m s^-1
- 5 m s^-1
-
What shape on a displacement-time graph represents constant non-zero velocity?
- Horizontal straight line
- Downward curved line
- Upward curved line
- Straight sloped line
-
How is total displacement calculated from a non-linear velocity-time graph?
- Area under curve
- Peak velocity value
- Gradient of chord
- Gradient of tangent
-
An object has zero acceleration from 0 to 2 s and then an acceleration of 3 m s^-2 from 2 s to 6 s. What is the change in velocity over the whole interval?
- 12 m s^-1
- 6 m s^-1
- 18 m s^-1
- 3 m s^-1
-
A velocity-time graph shows velocity falling from 8 m s^-1 to 2 m s^-1 in 3 s. What is the acceleration?
- -2 m s^-2
- -0.67 m s^-2
- +2 m s^-2
- -6 m s^-2
-
What quantity is given by the gradient of a tangent to a displacement-time graph?
- Instantaneous velocity
- Total displacement
- Average velocity
- Instantaneous acceleration
-
What feature of a velocity-time graph represents a larger magnitude of acceleration?
- Steeper gradient
- Flatter gradient
- Area under curve
- Horizontal line
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