Lesson 3.7.3.2
3.7.3.2 Electric field strength Quiz: AQA Physics, Unit 7
20 questions
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Lesson 3.7.3.2, Electric field strength: 20 multiple choice questions for the AQA Physics (7408), Unit 7: Fields and their consequences (A-level only), written with Revision Ninja.
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The 20 questions
-
How is electric field strength defined at a point in an electric field?
- Force per unit charge
- Charge per unit force
- Work per unit charge
- Energy per unit distance
-
The field strength in a uniform field between parallel plates is:
- E = V / d
- E = V / d^2
- E = V d
- E = d / V
-
What equation gives the uniform electric field strength E between two parallel plates?
- E = V / d
- E = V x d
- E = V / q
- E = F / d
-
The field strength in a radial field at distance r from a point charge Q is:
- E = Q / (4 pi eps0 r)
- E = Q / (4 pi eps0 r^3)
- E = 4 pi eps0 Q / r^2
- E = Q / (4 pi eps0 r^2)
-
What is the direction of electric field lines around charged particles?
- Negative to positive
- Positive to negative
- Positive to positive
- Clockwise around charge
-
What path does a charged particle take when entering a uniform electric field perpendicularly?
- Linear
- Circular
- Helical
- Parabolic
-
The SI unit of electric field strength is:
- V C^-1
- N m C^-1
- C m^-1
- N C^-1, equivalent to V m^-1
-
A charge of 3.0 microcoulomb experiences a force of 0.060 N in an electric field. What is the field strength?
- 2.0 x 10^7 N C^-1
- 1.8 x 10^-7 N C^-1
- 2.0 x 10^-2 N C^-1
- 2.0 x 10^4 N C^-1
-
Two parallel plates 5.0 cm apart have a pd of 200 V across them. What is the uniform field strength?
- 1.0 x 10^4 V m^-1
- 4.0 x 10^3 V m^-1
- 4.0 x 10^1 V m^-1
- 4.0 x 10^5 V m^-1
-
An electron is in a uniform field of strength 4.0 x 10^3 V m^-1. Estimate the force on the electron (e = 1.6 x 10^-19 C).
- 6.4 x 10^-16 N
- 6.4 x 10^-13 N
- 6.4 x 10^-19 N
- 2.5 x 10^-23 N
-
The field strength at 2.0 m from a point charge of 4.0 microcoulomb is approximately:
- 1.8 x 10^4 N C^-1
- 9.0 x 10^3 N C^-1
- 4.5 x 10^3 N C^-1
- 9.0 x 10^4 N C^-1
-
If the distance from a point charge is doubled, the electric field strength becomes:
- one half
- one quarter
- twice
- unchanged
-
A proton (charge 1.6 x 10^-19 C, mass 1.67 x 10^-27 kg) is in a uniform field of 1000 N C^-1. What is its acceleration?
- about 9.6 x 10^8 m s^-2
- about 9.6 x 10^10 m s^-2
- about 1.0 x 10^3 m s^-2
- about 9.6 x 10^12 m s^-2
-
What type of electric field is created between two oppositely charged parallel plates?
- Radial field
- Dipole field
- Uniform field
- Zero field
-
What is the direction of the net electric field at the midpoint between equal opposite charges?
- Towards negative charge
- Zero field
- Perpendicular to line
- Towards positive charge
-
A point is 3.0 m from a point charge, which gives field strength E. The field strength at 1.0 m from the same charge is:
- 6 times E
- E/9
- 3 times E
- 9 times E
-
Charges +2.0 microcoulomb and -2.0 microcoulomb are 0.10 m apart. A point P is on the perpendicular bisector, 0.050 m from the midpoint. What is the magnitude of the field at P?
- about 3.6 x 10^6 N C^-1
- about 1.8 x 10^6 N C^-1
- about 7.2 x 10^6 N C^-1
- about 5.1 x 10^6 N C^-1
-
An electron is in a uniform field of 500 N C^-1. Estimate its acceleration (e = 1.6 x 10^-19 C, m_e = 9.11 x 10^-31 kg).
- about 1.6 x 10^-16 m s^-2
- about 8.8 x 10^11 m s^-2
- about 8.8 x 10^13 m s^-2
- about 8.8 x 10^16 m s^-2
-
How many directions would an electric field have at a point where field lines crossed?
- Two
- Zero
- One
- Infinite
-
An electron is accelerated across a 0.10 m region of uniform field of 2.0 x 10^3 V m^-1. What energy does it gain, in electronvolts?
- 0.2 eV
- 2000 eV
- 200 eV
- 20 eV
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