Lesson 4C.3.3
4C.3.3 Toppling and sliding of rigid bodies Quiz: Pearson Edexcel Further Maths, Unit 32
20 questions
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Lesson 4C.3.3, Toppling and sliding of rigid bodies: 20 multiple choice questions for the Pearson Edexcel Further Maths (9FM0), Unit 32: Centres of mass and equilibrium of rigid bodies, written with Revision Ninja.
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The 20 questions
-
Where does the vertical line through the centre of mass pass when a rigid box topples?
- Inside base
- Beyond base edge
- Through the centre
- Above top edge
-
What condition on the inclination angle theta causes a body on a rough plane to slide?
- cos theta > mu
- tan theta > mu
- theta > 45 degrees
- sin theta > mu
-
A uniform block has base half-width b and centre of mass at height h above the base, on a slope of angle theta. Which condition gives toppling?
- tan theta > h/b
- tan theta < b/h
- tan theta > 2b/h
- tan theta > b/h
-
What does the friction force equal when a body is on the point of sliding?
- mu R
- R / mu
- mu / R
- zero
-
Where does the normal reaction act when a block is on the verge of toppling?
- Distributed evenly
- At the pivot edge
- Outside the base
- At the centre
-
What condition ensures a pushed block on a horizontal plane does not topple?
- Normal force zero
- Height exceeds width
- Friction exceeds force
- Weight line in base
-
In which direction does friction act when a block is about to slide up a rough incline?
- down the slope
- up the slope
- vertically upwards
- horizontally
-
What physical parameter represents the maximum angle of a rough incline before sliding occurs?
- Angle of friction
- Limiting angle
- Critical angle
- Toppling angle
-
A uniform box with a square base of width 0.6 m has its centre of mass 0.8 m above the base. What is the critical value of tan theta for toppling on a slope?
- 1.33
- 0.3
- 0.375
- 0.75
-
What is the state of a block if tipping moments about its lower edge exactly balance?
- accelerating
- stable equilibrium
- sliding
- verge of toppling
-
A 5 kg block rests in equilibrium on a rough slope at 20 degrees without sliding (g = 10 m/s^2). What is the friction force?
- 17.1 N
- 18.2 N
- 47.0 N
- 1.7 N
-
A block is on the point of sliding on a rough plane with coefficient of friction 0.75. What is the angle of the plane?
- 36.9 degrees
- 48.8 degrees
- 41.4 degrees
- 53.1 degrees
-
For a uniform block on a rough slope, what condition ensures it topples before sliding?
- b/h = mu
- b/h > mu
- b/h < mu
- h/b < mu
-
A 4 kg block rests on a rough horizontal floor with coefficient 0.3 (g = 10 m/s^2). It is pushed horizontally with 10 N and stays at rest. What is the friction force?
- 12 N
- 40 N
- 0 N
- 10 N
-
A 2 kg block is on a rough slope where tan theta = 0.5 and friction is limiting (g = 10 m/s^2). What is the normal reaction?
- 8 sqrt(5) N, about 17.9 N
- 4 sqrt(5) N, about 8.9 N
- 20 N
- 10 N
-
A block has base half-width 0.4 m and centre of mass height 1.2 m, and rests on a rough slope with coefficient 0.6. As the slope angle increases, what happens first?
- Sliding, at tan theta = 0.6
- Toppling, at tan theta = 0.6
- Toppling, at tan theta = 1/3
- Sliding, at tan theta = 1/3
-
A uniform cube of side a rests on a rough slope with coefficient of friction greater than 1. At what slope angle does it topple?
- arctan(2), about 63.4 degrees
- 30 degrees
- 45 degrees
- 60 degrees
-
A uniform block of weight 50 N has base half-width 0.2 m and centre of mass height 0.5 m. It is pushed horizontally at the height of its centre of mass on a rough floor. What push first causes toppling?
- 50 N
- 20 N
- 5 N
- 10 N
-
What geometric property of a rigid body makes toppling occur before sliding on an incline?
- Narrow base
- Smooth surface
- Heavy mass
- Wide base
-
A block has b/h = 0.5 and coefficient of friction 0.8 on a rough slope. At what angle does it first move, and how?
- 14.0 degrees, by toppling
- 26.6 degrees, by toppling
- 45 degrees, by sliding
- 38.7 degrees, by sliding
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