Lesson 3.1.9.1
3.1.9.1 Rate equations Quiz: AQA Chemistry, Unit 1
20 questions
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Lesson 3.1.9.1, Rate equations: 20 multiple choice questions for the AQA Chemistry (7405), Unit 1: Physical chemistry, written with Revision Ninja.
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The 20 questions
-
In the rate equation Rate = k[A]ᵐ[B]ⁿ, what does the exponent m represent?
- Stoichiometric coefficient
- Overall order
- Rate constant
- Order of A
-
Which factor directly changes the value of the rate constant k for a given reaction?
- Concentration
- Pressure
- Surface area
- Temperature
-
Which set of values are reactant orders restricted to at A-level Chemistry?
- 1 and 2 only
- 0, 1 and 2
- 1, 2 and 3
- -1, 0 and 1
-
A reaction has the rate equation Rate = k[A][B]. What are the units of k when concentrations are in mol dm^-3 and rate in mol dm^-3 s^-1?
- s^-1
- dm^3 mol^-1 s^-1
- mol dm^-3 s^-1
- mol^-1 dm^3
-
A first-order reaction has Rate = k[A]. What are the units of k?
- s^-1
- dm^3 mol^-1 s^-1
- dm^6 mol^-2 s^-1
- mol dm^-3 s^-1
-
A zero-order reaction has Rate = k. What are the units of k when rate is in mol dm^-3 s^-1?
- dm^3 mol^-1 s^-1
- mol dm^-3 s^-1
- mol^-1 dm^3 s
- s^-1
-
For a reaction with Rate = k[A]^2 and k = 0.50 dm^3 mol^-1 s^-1, what is the rate when [A] = 0.20 mol dm^-3?
- 0.0080 mol dm^-3 s^-1
- 0.40 mol dm^-3 s^-1
- 0.020 mol dm^-3 s^-1
- 0.10 mol dm^-3 s^-1
-
For Rate = k[A][B]^2 with k = 2.0 dm^6 mol^-2 s^-1, [A] = 0.10 and [B] = 0.20 mol dm^-3, what is the rate?
- 0.10 mol dm^-3 s^-1
- 0.040 mol dm^-3 s^-1
- 0.0080 mol dm^-3 s^-1
- 0.0040 mol dm^-3 s^-1
-
How does an increase in temperature affect the rate constant k of a reaction?
- It becomes zero
- It increases
- It decreases
- It stays constant
-
Which rearrangement of k = Ae^(-Ea/RT) allows a straight-line graph of experimental data to be plotted?
- ln k = -Ea/(RT) + ln A
- k = -Ea/(RT) + A
- ln k = Ea/(RT) - ln A
- 1/k = Ea/(RT) + A
-
The rate constant k is measured at several temperatures. What is the gradient of a graph of ln k against 1/T?
- Ea/R
- ln A
- -Ea/R
- -R/Ea
-
For a reaction with k = A e^(-Ea/RT), A = 1.0 x 10^10 s^-1, Ea = 60 kJ/mol and T = 300 K, what is k? Use R = 8.314 J K^-1 mol^-1.
- About 36 s^-1
- About 0.036 s^-1
- About 0.36 s^-1
- About 3.6 s^-1
-
What is the gradient of a concentration–time graph for a zero-order reaction?
- -k
- +k
- 1/k
- Zero
-
Doubling the concentration of reactant B has no effect on rate. What is the order with respect to B?
- Second order
- Half order
- Zero order
- First order
-
The rate equation is Rate = k[A][B]^2. By what factor does the rate increase when [A] is tripled and [B] is doubled?
- 24
- 9
- 12
- 6
-
Initial rate data: [A] = 0.10, [B] = 0.10 mol dm^-3 gives rate 2.0 x 10^-3 mol dm^-3 s^-1; [A] = 0.20, [B] = 0.10 gives rate 8.0 x 10^-3. With Rate = k[A]^2, what is k?
- 0.20 dm^3 mol^-1 s^-1
- 2.0 dm^3 mol^-1 s^-1
- 0.020 dm^3 mol^-1 s^-1
- 0.50 dm^3 mol^-1 s^-1
-
If Rate = k[A]², how many molecules of A are in the rate-determining step?
- Two
- Three
- Zero
- One
-
How must the orders of reaction in a rate equation always be determined?
- From balanced equations
- Experimentally
- From stoichiometry
- From molar masses
-
A reaction is first order in A, with Rate = k[A]. If [A] is doubled at constant temperature, what happens to the rate?
- It is unchanged
- It doubles
- It halves
- It quadruples
-
For Rate = k[A]², by what factor does the rate change if [A] is halved?
- One quarter
- One half
- Double
- One eighth
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