Lesson 13B.2
13B.2 Calculating entropy changes Quiz: Pearson Edexcel Chemistry, Unit 13
20 questions
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Lesson 13B.2, Calculating entropy changes: 20 multiple choice questions for the Pearson Edexcel Chemistry (9CH0), Unit 13: Energetics II, written with Revision Ninja.
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The 20 questions
-
How is the standard entropy change of a system calculated?
- S(reactants) - S(products)
- S(surroundings) - S(system)
- S(products) + S(reactants)
- S(products) - S(reactants)
-
Which factor has the largest effect on the magnitude of a substance's standard entropy?
- Chemical formula
- Physical state
- Molar mass
- Bond enthalpy
-
What is the entropy value of a perfect crystal at absolute zero?
- 0 J K⁻¹ mol⁻¹
- -273 J K⁻¹ mol⁻¹
- 100 J K⁻¹ mol⁻¹
- 298 J K⁻¹ mol⁻¹
-
Why do gases have significantly higher standard entropies than liquids?
- Higher particle density
- Stronger intermolecular forces
- Greater particle freedom
- Fixed particle positions
-
What does a negative entropy change of a system indicate?
- Unchanged order
- Increased enthalpy
- Increased disorder
- Increased order
-
Which substance has the highest standard entropy at 298 K?
- Diamond(s)
- H2O(l)
- All are equal
- CO2(g)
-
What sign is the standard entropy of a pure element at 298 K?
- Negative
- Positive
- Variable
- Zero
-
For N2(g) + 3H2(g) gives 2NH3(g), with S(N2) = 191.5, S(H2) = 130.7 and S(NH3) = 192.8 J K-1 mol-1, what is dS for the system?
- -198.0 J K-1 mol-1
- +775.2 J K-1 mol-1
- -391.2 J K-1 mol-1
- +198.0 J K-1 mol-1
-
For CaCO3(s) gives CaO(s) + CO2(g), with S(CaCO3) = 92.9, S(CaO) = 39.8 and S(CO2) = 213.8 J K-1 mol-1, what is dS for the system?
- +266.9 J K-1 mol-1
- -160.7 J K-1 mol-1
- +160.7 J K-1 mol-1
- +346.5 J K-1 mol-1
-
For 2Mg(s) + O2(g) gives 2MgO(s), with S(Mg) = 32.7, S(O2) = 205.2 and S(MgO) = 26.9 J K-1 mol-1, what is dS for the system?
- -216.8 J K-1 mol-1
- +270.6 J K-1 mol-1
- -54.5 J K-1 mol-1
- +216.8 J K-1 mol-1
-
For H2O(l) gives H2O(g), with S(l) = 70.0 and S(g) = 188.8 J K-1 mol-1, what is dS for the system?
- -118.8 J K-1 mol-1
- +258.8 J K-1 mol-1
- +118.8 J K-1 mol-1
- +70.0 J K-1 mol-1
-
For N2O4(g) gives 2NO2(g), with S(N2O4) = 304.3 and S(NO2) = 240.0 J K-1 mol-1, what is dS for the system?
- +544.3 J K-1 mol-1
- +175.7 J K-1 mol-1
- +64.3 J K-1 mol-1
- -175.7 J K-1 mol-1
-
For CH4(g) + 2O2(g) gives CO2(g) + 2H2O(l), with S(CH4) = 186.3, S(O2) = 205.2, S(CO2) = 213.8 and S(H2O, l) = 69.9 J K-1 mol-1, what is dS for the system?
- +596.7 J K-1 mol-1
- -43.1 J K-1 mol-1
- +243.1 J K-1 mol-1
- -243.1 J K-1 mol-1
-
For a combustion reaction with dH = -890 kJ mol-1 at 298 K, what is the entropy change of the surroundings?
- +890 J K-1 mol-1
- +2.99 J K-1 mol-1
- +2987 J K-1 mol-1
- -2987 J K-1 mol-1
-
Convert dS = -243.1 J K-1 mol-1 into kJ K-1 mol-1.
- -2.431 kJ K-1 mol-1
- -24.31 kJ K-1 mol-1
- -0.2431 kJ K-1 mol-1
- -0.02431 kJ K-1 mol-1
-
For a reaction with dS(system) = -243.1 J K-1 mol-1, dH = -890 kJ mol-1 and T = 298 K, what is dStotal?
- +2743.5 J K-1 mol-1
- -3229.7 J K-1 mol-1
- +3229.7 J K-1 mol-1
- -2743.5 J K-1 mol-1
-
Which entropy change determines whether a chemical reaction is spontaneous?
- System entropy change
- Enthalpy change
- Surroundings entropy change
- Total entropy change
-
A reaction has dSsystem = -240 J K-1 mol-1 and dH = -120 kJ mol-1. At what temperature is dStotal equal to zero?
- 500 K
- 250 K
- 50 K
- 2 K
-
For ΔSsystem = +100 J K-1 mol-1 and ΔH = +30 kJ mol-1 at 298 K, what is ΔStotal?
- +0.7 J K-1 mol-1
- -0.7 J K-1 mol-1
- +199.3 J K-1 mol-1
- -0.1 J K-1 mol-1
-
When calculating ΔStotal, what unit conversion must be applied to ΔH in kJ mol-1?
- Multiply by 1000
- Multiply by 298
- Divide by 298
- Divide by 1000
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